I have a piece of code here that is supposed to return the least common element in a list of elements, ordered by commonality: def getSingle(arr): from collections import Counter c = Counte...

The first, [:], is creating a slice (normally often used for getting just part of a list), which happens to contain the entire list, and thus is effectively a copy of the list. The second, list(), is using the actual …

The first way works for a list or a string; the second way only works for a list, because slice assignment isn't allowed for strings. Other than that I think the only difference is speed: it looks like it's a little …

If your list of lists comes from a nested list comprehension, the problem can be solved more simply/directly by fixing the comprehension; please see How can I get a flat result from a list …

May 30, 2013 · For example list and start of containers are now subcommands of docker container and history is a subcommand of docker image. These changes let us clean up the Docker CLI syntax, …

The notation List<?> means "a list of something (but I'm not saying what)". Since the code in test works for any kind of object in the list, this works as a formal method parameter. Using a type parameter …

Oct 5, 2017 · @Sandy Chapman: List.of does return some ImmutableList type, its actual name is just a non-public implementation detail. If it was public and someone cast it to List again, where was the …

Sep 17, 2016 · Possible Duplicate: Get difference from two lists in Python What is a simplified way of doing this? I have been trying on my own, and I can't figure it out. list a and list b, the new list should

Nov 29, 2016 · (List<Customer>)(Object)list; you must be sure that at runtime the list contains nothing but Customer objects. Critics say that such casting indicates something wrong with your code; you …

Apr 22, 2013 · The second action taken was to revert the accepted answer to its state before it was partway modified to address "determine if all elements in one list are in a second list".